A man is 2,000 m from the base of a tower and is launching a rocket in the direction of the same tower. When the rocket takes off the change in the angle between the flight path and the land is represented by Î¦(t) according to time. Knowing that Î¦'(t) = Î /3, determine:
1. The height of the rocket when Î¦ = Î /3 radians.
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Please explain how you arrived at your answer.